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02-28-2013, 01:16 PM
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radical x is the same as x to the 1/2 power... if it's x^(1/2) divided by x^2, you have x^(-3/2).

Originally Posted by Parker McDonald View Post
Yep. I got up to the step where I needed to divide the numerator and the denominator by x raised to the highest exponent in the denominator, which would be x^2, but since the denominator had a radical sign, I didn't know how to get the x^2 in there.

I was able to do it for the numerator, so that's how I got the 0. With my luck as a Ranger fan, the denominator is probably equal to 0 and I'll be wrong.


Last edited by Jabroni: 02-28-2013 at 01:27 PM.
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